Tentukan besar sudut tqr
∠PQR = 2x + (3x + 20°)
180° = 5x + 20°
5x = 180° - 20°
5x = 160°
x = 32°
∠TQR = 3x + 20°
∠TQR = 3(32°) + 20°
∠TQR = 96° + 20°
∠TQR = 116°
Penjelasan dengan langkah-langkah:
2x + 3x + 20 = 180
5x + 20 = 180
5x = 180 - 20
5x = 160
x = 160/5
x = 32
<TQR
3x + 20
3(32) + 20
96 + 20
116°
semoga membantu
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